How do I solve this problem.
I try just 1 than just 4
nether were right, than I try 4/4r
the Problem is 4Pr
Thank you
nPr=n!/(n-r)!
4Pr=4!/(4-r)!=24/(4-r)!
unless you know the value of r, this is the furthest we can go.
in general for n items taken r at a time
P(n,r) = n!/ (n-r)!
for n = 4 and r at a time
P(4,r) = 4!/(4-r)!
so for 4 taken 1 at a time
4!/3! = 4*3*2*1/(3*2*1) = 4
or for 4 taken 2 at a time
4!/(2)! = 4*3 *2*1/2*1 = 12
thank you Damon
To solve the given problem 4Pr, where r is the number of choices or objects to be selected, we need to use the concept of permutations.
A permutation is an arrangement of objects in a specific order. In this case, we are selecting r objects from a set of 4 objects.
Here's how you can approach solving this problem step by step:
1. Understand the formula: The formula for permutations is given by nPr = n! / (n - r)!, where n represents the total number of objects and r represents the number of objects to be selected.
2. Calculate the factorial: The exclamation mark (!) denotes the factorial operation. To calculate the factorial of a number, you multiply all the integers from that number down to 1. For example, 4! = 4 x 3 x 2 x 1 = 24. Similarly, (4 - 1)! = 3! = 3 x 2 x 1 = 6.
3. Substitute the values: Plug in the values of n and r into the formula. In this case, n = 4 and r = 4, so the formula becomes 4P4 = 4! / (4 - 4)! = 4! / 0!.
4. Simplify the equation: Since the denominator 0! = 1 (by convention), the equation becomes 4! / 1 = 24 / 1 = 24.
Therefore, the solution to the problem 4Pr, where r = 4, is equal to 24.
Remember that the formula for permutations (nPr) can be used to calculate the number of arrangements when the order matters and repetition is not allowed.