Suppose you spin a spinner that is equally likely to land on any one of the numbers from 1 to 8. Which event has the same probability as P(not 2 or 3)?
p(2 or 3) p (even) p (morn than 6) P (less than 7)
There are several. What are your choices?
less than 7
To determine the event that has the same probability as P(not 2 or 3), we first need to find the probability of the event "not 2 or 3".
Let's start by finding the probability of landing on 2 or 3. Since the spinner is equally likely to land on any number from 1 to 8, there are 8 possible outcomes in total.
The event "not 2 or 3" consists of all the outcomes that are not 2 or 3, which means there are 6 possible outcomes (1, 4, 5, 6, 7, 8) that fulfill this condition.
Therefore, the probability of landing on 2 or 3 is 2/8 or 1/4, and the probability of not landing on 2 or 3 is 6/8 or 3/4.
Now, we need to find the event that has the same probability as P(not 2 or 3), which is 3/4.
There are multiple events that satisfy this condition. For example, the event "landing on an even number" also has a probability of 3/4.
To calculate this probability, we can determine the number of favorable outcomes (even numbers) and divide it by the total number of possible outcomes (8).
Since there are four even numbers (2, 4, 6, 8) and eight possible outcomes, the probability of landing on an even number is 4/8 or 1/2.
Therefore, the event "landing on an even number" has the same probability as P(not 2 or 3), which is 3/4.