Find the general form of the equation for the line with the given properties
Slope=-5/8 ; containing the point (0,4)
Since you are given the slope and the y-intercept, the problem becomes a matter of just subbing in the values
y = (5/8)x + 4
My teachers answer was 5x+8y=32
Your answer is clearly wrong..
It's asking for general form, not slope-intercept
It is true that Reiny's answer has a typo.
Recognizing that, fix it and rearrange it into the desired form of the equation.
To find the equation for a line with a given slope and containing a specific point, you can use the point-slope form of the equation, which is:
y - y1 = m(x - x1)
where (x1, y1) represents the coordinates of the point that the line passes through, and m represents the slope of the line.
In this case, the given slope is -5/8, and the line contains the point (0,4). Plugging these values into the point-slope form, we get:
y - 4 = (-5/8)(x - 0)
Simplifying this equation gives us:
y - 4 = (-5/8)x
To put it in general form, we can multiply both sides of the equation by 8 to eliminate the fraction:
8(y - 4) = -5x
Expanding:
8y - 32 = -5x
Rearranging the terms to have the variables on the left and the constants on the right gives us:
5x + 8y = 32
So, the general form of the equation for the line with a slope of -5/8 and passing through the point (0,4) is 5x + 8y = 32.