# Physics

A heat engine has a hot reservoir of 680°C and a cold reservoir of 220°C. What is the efficiency of the engine?

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1. I do not know but I can tell you the MAXIMUM efficiency which is that of a Carnot cycle

High temp = 680 + 273 = 953 Kelvin
Low Temp = 220 + 273 = 493 Kelvin

Carnot efficiency = 100*(hot-cold)/hot
= 100 (953-493)/953
= 48.3 %

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posted by Damon

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