# Math Probability

Let X and Y be independent random variables, each uniformly distributed on the interval [0,2].

Find the mean and variance of XY.

E[XY]=

var[XY]=

Find the probability that XY≥1. Enter a numerical answer.

P(XY≥1)=

1. 👍 0
2. 👎 0
3. 👁 367
1. E[XY] = 1
var[XY] = 7/9
p(XY >= 1) = ??

1. 👍 0
2. 👎 0
2. p(XY >= 1) = 2/5

1. 👍 0
2. 👎 0
3. p(XY >= 1) = 0.40343

1. 👍 0
2. 👎 0

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