A company has 140 employees, of which 30 are supervisors. Eighty of the employees are
married, and 20% of the married employees are supervisors. If a company employee is
randomly selected, what is the probability that the employee is married and is a supervisor?
{20/100}×80= 16
16/140= 0.114
Supervisors = 30/140
Married = 64/140
Married supervisors = 16/140
So the probability that the employee is married and is a supervisor is 16/140 = 0.11
To find the probability that an employee is both married and a supervisor, we need to calculate the proportion of employees that satisfy both conditions.
First, let's calculate the number of married employees who are supervisors. We know that 20% of the married employees are supervisors, and since there are 80 married employees, the number of married employees who are supervisors is 20% of 80:
Number of married employees who are supervisors = 0.20 * 80 = 16.
Now, we can calculate the probability by dividing the number of employees who satisfy both conditions (married and supervisor) by the total number of employees.
Probability = Number of employees who are married and supervisors / Total number of employees.
Total number of employees = 140 (given in the question).
Probability = 16 / 140 = 0.1143 (rounded to four decimal places).
Therefore, the probability that a randomly selected employee is married and a supervisor is approximately 0.1143 or 11.43%.
8 * .2 = 1.6 rounded to 2 are married and supervisors.
2/140 = ?
80 * .2
16