there are 4 blue tile,s 3 yellow tiles, 5 red tiles, and 2 green tiles.

he draws a tile replaces it, and draws another tile. what is the probability he will draw a blue tile on both

(4/15)^2 = 16/225

16/225

maybe if u stanned steve u would get 100% on ur math test smh

Now now Stevie lets be kind hehehe

and why do you post the answer if ur wrong like lmao fact check urself

To find the probability of drawing a blue tile on both draws, we need to calculate the probability of drawing a blue tile on the first draw and then drawing another blue tile on the second draw.

The total number of tiles is 4 + 3 + 5 + 2 = 14.

The probability of drawing a blue tile on the first draw is 4/14 because there are 4 blue tiles out of a total of 14 tiles.

After replacing the first tile (assuming it is placed back into the pool of tiles), the total number of tiles remains 14.

Thus, the probability of drawing a blue tile on the second draw is also 4/14 since the number of blue tiles and the total number of tiles did not change.

To find the probability of both events happening, we multiply the probabilities of the two events together:

(4/14) * (4/14) = 16/196 = 4/49

Therefore, the probability of drawing a blue tile on both draws is 4/49.

sorry 3 green tiles

2/35
1/9
16/225
2/21

?

Bro no one likes Steve

4+3+5+2 = 14

two independent 4/14 draws
(2/7)^2 = 4/49 = .0816

4/14

:D hope that helps