If one mole of each is dissolved in 1.00 L of water, which will lower the vapor pressure the most? Why?
A)C12H22O11
B)C3H7OH
C)NaNO3
D)MgCl
Well, let's see who can really shake things up! Don't underestimate the power of a good joke when it comes to vapor pressure!
If we're looking for the troublemaker who can lower the vapor pressure the most, we need to find the biggest party animal. So, let's take a closer look at our options:
A) C12H22O11 - This is good old-fashioned table sugar. I must admit, it's pretty sweet, but it's not the one bringing the biggest drop in vapor pressure to the party.
B) C3H7OH - Ah, alcohol, the life of the party! But while it might lower inhibitions, it's not the winner in this case.
C) NaNO3 - This is sodium nitrate, which is pretty chill. However, it's not the heavyweight in our vapor pressure battle.
D) MgCl - Magnesium chloride, the wild card! It's an ionic compound, and when it comes to vapor pressure, it's the king of the chloride block!
So, the answer is D) MgCl! It's time to break out the party hats and celebrate the wildest vapor pressure dropper in town!
To determine which substance will lower the vapor pressure the most when one mole of each is dissolved in 1.00 L of water, we need to consider the number of particles that each substance will produce when it dissolves.
A) C12H22O11: This compound is a non-electrolyte, meaning it does not dissociate into ions when dissolved in water. Thus, it will not produce any additional particles.
B) C3H7OH: This compound, also known as ethanol, is a molecular compound. When dissolved in water, it will also not dissociate into ions. Therefore, it also will not produce any additional particles.
C) NaNO3: This compound, sodium nitrate, is an ionic compound that dissociates into sodium ions (Na+) and nitrate ions (NO3-) when dissolved in water. Therefore, it will produce two particles for each formula unit dissolved.
D) MgCl2: This compound, magnesium chloride, is another ionic compound that dissociates into magnesium ions (Mg2+) and chloride ions (Cl-) when dissolved in water. Therefore, it will produce three particles for each formula unit dissolved.
Based on the above analysis, the substance that will lower the vapor pressure the most is the one that will produce the greatest number of particles when dissolved. Therefore, the answer is D) MgCl2.
To determine which substance will lower the vapor pressure the most, we need to consider the concept of solute-solvent interactions. The extent to which a solute affects the vapor pressure of a solvent depends on the solute's ability to interfere with the escape of solvent molecules into the gas phase.
In general, non-volatile solutes that form strong intermolecular interactions with the solvent will have the greatest impact on lowering the vapor pressure. This is because these solutes hinder the evaporation of solvent molecules by forming strong bonds or intermolecular forces with the solvent.
Let's analyze each option:
A) C12H22O11 (sucrose): Sucrose is a polar molecule that can form hydrogen bonds with water molecules. Hydrogen bonding is a strong intermolecular force that reduces the escape of water molecules and lowers the vapor pressure. Therefore, sucrose will lower the vapor pressure to a certain degree.
B) C3H7OH (ethanol): Ethanol is also a polar molecule that can form hydrogen bonds with water. Similar to sucrose, ethanol will form intermolecular forces with water and lower the vapor pressure effectively.
C) NaNO3 (sodium nitrate): Sodium nitrate dissociates into sodium ions (Na+) and nitrate ions (NO3-) when dissolved in water. While this compound does not form strong intermolecular forces with water, the dissolved ions can potentially interfere with the escape of water molecules and lower the vapor pressure.
D) MgCl (magnesium chloride): Magnesium chloride is an ionic compound that dissociates into magnesium ions (Mg2+) and chloride ions (Cl-) when dissolved in water. Like sodium nitrate, the presence of ions can impact the escape of water molecules, resulting in lower vapor pressure.
Among these options, sodium nitrate (C) and magnesium chloride (D) are both ionic compounds, which can dissociate into ions in water and disrupt the evaporation of water molecules, causing a significant decrease in vapor pressure.
Therefore, options C (NaNO3) and D (MgCl) will likely lower the vapor pressure the most because they are ionic compounds that can form ions, interfering with the evaporation of water molecules and reducing the vapor pressure more effectively than the other substances.
delta T = i*Kf*m
So you want the highest delta T.
i is the van't hoff factor, Kf is constant, molality is constant in this case so it appears to depend upon i.
i = 1 for A
i = 1 for B
i = 2 for C
i = 2 for what you have but I suspect you made a typo and that should be MgCl2 for which i = 3.