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Roughly speaking, the standard deviation indicates how far, on average, the observations are from the mean. Do you think that for the data set below the standard deviation will give a good indication of the typical deviation from
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Find the range and the standard deviation (correct to two decimal places). 83, 96, 100, 100, 106=divided by 5=97 I did the (8397)+(9697)+(10097)+(100+97)=10697)= I know I add than divide by 5 and I can not come up with
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Assume that a standardized test is designed to have the mean score of 100 and the standard deviation of 15. At the 95% confidence interval, how large does the sample size have to be if the margin of error is to be 3 points?
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Assume that a standardized test is designed to have the mean score of 100 and the standard deviation of 15. At the 95% confidence interval, how large does the sample size have to be if the margin of error is to be 3 points?
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Use a calculator to find the mean and standard deviation of the data. Round to the nearest tenth. 6,7,19,7,18,7 A. mean = 9; standard deviation = 26.4 B. mean = 11.9; standard deviation = 26.4 C. mean = 10.6; standard deviation =
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If a distribution of IQ test scores has a mean of 100 and a standard deviation of 16, what would be the result if we first subtract the mean (100) from each score, and then divide each of those resulting scores by the standard
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