algebra

A machine launches a tennis ball directly upward at 64 feet per second from a platform that is 80 feet high.

what is the maximum height of the tennis ball?

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  1. h max = ho + (V^2-Vo^2)/2g
    h max = 80 + (0-(64^2))/-64 = 144 Ft
    above gnd.

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    posted by Henry

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