physics

A simple lever is used to lift a heavy load. When a 60-N force pushes one end of the lever down 1.2 m, the load rises 0.2 m. Show that the weight of the load is 360 N.

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asked by Peg
  1. Work done by force = work done by load (W)

    60 N * 1.2 m = 0.2 m * W

    Solve for W to get
    W=60*1.2/0.2 N
    = 360 N

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  2. 60N x 1.2m =0.2 x the weight of the load.
    As 60 x 1.2/0.2=360N
    shown

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    posted by potato

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