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prove: 1/log(base36)a = 2/log(base6)a i made a common base and then multiplied both sides with log(base6)a to get 2=log(base6)a/log(base6^2)a but this is as far as i can figure.
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solve for x: 3^2x+3=7^x+1 I did 2x+3=log0f3(7)+ logof3(7) (2log of 3(7))x=log of 3(7)3 x=log of 3 (7)+log of 3 (3^3)/log 0f 3 (3^2)log of 3 (7) x=log of 3 (71/3^3)/log of 3(9/7) log of 3(7/27)/log of 3(9/7) answer log of
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