use integer values of x from -3 to graph the equation.
(the x has a 2 above it,like to the second power) y=-2x+3
I don't know how to do this kind of math.
If y = -2x^2 + 3, then just use the values of x and calculate the values of y:
x y
-3 -2(9)+3 = -15
-2 -2(4)+3 = -5
-1 -2(1)+3 = 1
0 -2(0)+3 = 3
1 1
2 -5
3 -15
Plot those points and sketch a smooth curve through them.
Your graph should look like the one given by wolframalpha:
http://www.wolframalpha.com/input/?i=-2x^2%2B3
The Y axis on the graph 6,5,4,3,2,1,0,-1,-2,-3,-4,-5,-6 and that's the end of that axis.
The X axis on the graph
-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6 and that's the end of that axis. So I don't know where to graph those points.
To graph the equation y = -2x + 3 using integer values of x from -3, we can follow a step-by-step process:
1. Choose the values of x: Select integer values of x from -3. Let's consider x = -3, -2, -1, 0, 1, 2, and 3.
2. Calculate the corresponding y-values: Substitute the chosen values of x into the equation y = -2x + 3 to find the corresponding y-values. For example, when x = -3, the calculation would be:
y = -2(-3) + 3
Simplifying, we get:
y = 6 + 3
y = 9
Repeat this process for each value of x to find the corresponding y-values.
3. Plot the points: Take each pair of (x, y) values and plot them on the graph. For example, the point (-3, 9) would be plotted on the coordinate plane.
4. Connect the points: After plotting all the points, connect them with a straight line to visualize the graph of the equation.
Following these steps, you can now plot the graph of the equation y = -2x + 3 using the provided integer values of x from -3.