How to figure out the temperature of a lake using x for the feet or the Depth and for the degrees Celsius, use (3900x+1000) /(3x^2+100) with the answer of the degrees Celsius being 6.74 looking like
6.74=(3900x+1000)/(3x^2+100)
i need the depth
i have figure out that
a=-20.22
b= 3900
c= 326
On the quadratic formula table
-3900+Square root ()/-40.44
Yes, the quadratic formula is:
x=(-b±√(b²-4ac))/(2a)
what you need inside the square-root sign is
b²-4ac
You will get two roots for x.
Reject the negative one, and retain the positive root which is a little under 200.
Thank you
My professor told me to go to the math lab and they could help on a white board thank you for all you help if I knew going back to school I wouldn't have done it at the wise age of 60
No problem.
Let us know any time if you need further help.
i do that just confused me even more
To find the depth of the lake using the given equation, you need to solve the equation for x. The equation is:
6.74 = (3900x + 1000)/(3x^2 + 100)
To simplify the equation, let's clear the fraction by multiplying both sides by (3x^2 + 100):
6.74 * (3x^2 + 100) = 3900x + 1000
Now, distribute 6.74 to both terms inside the parentheses:
20.22x^2 + 674 - 674 = 3900x + 1000
Combine like terms:
20.22x^2 = 3900x + 1000 - 674
20.22x^2 = 3900x + 326
Next, let's move all the terms to one side to form a quadratic equation:
20.22x^2 - 3900x - 326 = 0
Now we have a quadratic equation in the form of ax^2 + bx + c = 0, where:
a = 20.22
b = -3900
c = -326
To find the value of x, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac))/(2a)
Substituting the values of a, b, and c into the formula:
x = (-(-3900) ± √((-3900)^2 - 4 * 20.22 * -326))/(2 * 20.22)
Simplifying further:
x = (3900 ± √(15,210,000 - (-26,646.24)))/(40.44)
x = (3900 ± √(15,236,646.24))/(40.44)
Now we can calculate the two possible values for x:
x = (3900 + √15,236,646.24)/(40.44) ≈ 3.52
or
x = (3900 - √15,236,646.24)/(40.44)
So, the possible values for the depth of the lake are approximately 3.52 feet and the other value you will get from the second equation.