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(2*log7 16)/(log3(√10+1)+log3(√10-1)log7 2

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Stasy

  1. I suspect a typo, since

    log3(√10+1)+log3(√10+1) = log3(10-1) = log3(9) = 2

    the log7 of powers of 2 is not amenable to simplification.

    Is there a typo? At the very least, the parentheses are not balanced.

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    Steve

  2. Fractions have implicit parenthese around the denominator and numerator.

    I have a feeling that the two log3 terms both belong to the denominator, in which case the expression should have been written, according to the BEDMAS rules,

    (2*log7 16)/((log3(√10+1)+log3(√10-1)log7 2 )

    in which case:
    (2*log724)/((log3(√10+1)(√10-1) log7 2 )
    =(8*log72)/((log3(10-1) log7 2 )
    =(8*log72)/((log3(9) log7 2 )
    =(8*log72)/(2 log7 2 )
    =4

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    MathMate

  4. Just a lucky guess, but you were right in the first place!

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    MathMate

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