math

the boys of a school can be arranged in 12,15 and 18 equals rows and also in to a solid square what is the least number of boys that the school can have.(hint find the LCM)

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asked by talha
  1. 12 = 2^2 * 3
    15 = 3*5
    18 = 2*3^2

    The smallest number which is a multiple of all of those must contain the highest power of each of the listed primes. So, that will be

    2^2 * 3^2 * 5 = 180

    But, we also want our number to be a perfect square, so we need to have 5^2 in the product.

    So, 180*5 = 900 is such a square

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    posted by Steve

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