# physics

A ball is projected horizontally from the top of a 98m high cliff with an initial speed of 14.4 m/s. Determine the magnitude of the final speed the instant prior to hitting the ground

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1. v = sqrt (2 g h)
u = 14.4
so
|V|= sqrt(u^2+v^2) = sqrt (2 g h + 14.4^2)

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posted by Damon

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