MATH

solve traingle ABC if A=63 degrees 10minutes, b=18 and a=17. Mark all solutions clearly.

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  1. SO
    A=63
    a=17
    B=?
    b=18
    C=?
    c=?
    using law of sines
    sine 63/17=sinB/18
    SinB= sin63x18/17
    ---------------'
    B=70.6 degrees '
    ---------------'
    to find C
    C= 180-63-70.6
    ----------------'
    C= 46.4 degrees '
    ----------------'
    using law of cosines
    c^2=17^2+18^2-2(17)(18)(cos(46.4))
    -------'
    c=13.8 '
    -------'

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  2. You ignored the 10 minutes of the 63º angle

    so A = 63.1667º which would slightly alter your angles.
    However I tested your solution for the angles if A = 63 and the angles are correct for that version

    your value of c is correct for A=63

    why did you use the cosine law?
    The Sine Law would have been easier.

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