Please help me go through this

F = q1q2/r^2, i know this is the equation, but i don't know how to get the answer, please help.

What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? Show your work. (µC = 1.0 × 10^–6 C)

(9x 10^9)/(.05m)^2, is this what i should be calculating?

F=KoQ1Q2/r^2

Where

Ko= 8.988 x 10^9 N*m^2/C^2
Q1=+2 µC=2 x 10^-9 C
Q2=-2 µC=-2 x 10^-9 C
and
r=5.0 cm=0.050 m

***Notice that Coulomb's constant contains meters and that it contains coulombs and not microcoulombs.

***Convert centimeters to meters and coulombs and not microcoulombs.

Solve for F:

F=(8.988 x 10^9 N*m^2/C^2)*(2 x 10^-9 C)(-2 x 10^-9 C)/(0.050 m)^2

F==(8.988 x 10^9 N*m^2/C^2)*(4 x 10^-18 C^2)/(0.050 m)^2

F=?

I'll let you take it from here.

ty so much :)

To find the electric force between two point charges using the given equation F = q1q2/r^2, you will need to substitute the values into the equation and solve for the electric force (F).

Given:
q1 = +2 µC = +2 × 10^–6 C
q2 = –2 µC = –2 × 10^–6 C
r = 5.0 cm = 5.0 × 10^–2 m

Now, let's substitute these values into the equation:

F = (q1 * q2) / r^2

F = (+2 × 10^–6 C) * (–2 × 10^–6 C) / (5.0 × 10^–2 m)^2

To multiply the charges, remember to multiply the numerical values and add the exponents of 10:

F = (2 * 10^–6) * (–2 * 10^–6) / (5.0 × 10^–2)^2

F = (–4 * 10^–12) / (5.0 × 10^–2)^2

Next, simplify the expression:

F = –4 * 10^–12 / (5.0 × 10^–2)^2

To square the term (5.0 × 10^–2)^2, square both the numerical value and the exponent:

F = –4 * 10^–12 / (5.0 × 10^–2 * 5.0 × 10^–2)

F = –4 * 10^–12 / (25 × 10^–4)

Now, rewrite 25 as 2.5 × 10:

F = –4 * 10^–12 / (2.5 × 10 * 10^–4)

Simplify and combine like terms:

F = –4 * 10^–12 / (2.5 × 10^–3)

Divide the numerical values and subtract the exponents of 10:

F = –1.6 × 10^–9 N

Therefore, the electric force between the +2 µC point charge and the –2 µC point charge separated by a distance of 5.0 cm is –1.6 × 10^–9 Newtons.