Please help me go through this
F = q1q2/r^2, i know this is the equation, but i don't know how to get the answer, please help.
What is the electric force between a +2 µC point charge and a –2 µC point charge if they are separated by a distance of 5.0 cm? Show your work. (µC = 1.0 × 10^–6 C)
(9x 10^9)/(.05m)^2, is this what i should be calculating?
F=KoQ1Q2/r^2
Where
Ko= 8.988 x 10^9 N*m^2/C^2
Q1=+2 µC=2 x 10^-9 C
Q2=-2 µC=-2 x 10^-9 C
and
r=5.0 cm=0.050 m
***Notice that Coulomb's constant contains meters and that it contains coulombs and not microcoulombs.
***Convert centimeters to meters and coulombs and not microcoulombs.
Solve for F:
F=(8.988 x 10^9 N*m^2/C^2)*(2 x 10^-9 C)(-2 x 10^-9 C)/(0.050 m)^2
F==(8.988 x 10^9 N*m^2/C^2)*(4 x 10^-18 C^2)/(0.050 m)^2
F=?
I'll let you take it from here.
ty so much :)
To find the electric force between two point charges using the given equation F = q1q2/r^2, you will need to substitute the values into the equation and solve for the electric force (F).
Given:
q1 = +2 µC = +2 × 10^–6 C
q2 = –2 µC = –2 × 10^–6 C
r = 5.0 cm = 5.0 × 10^–2 m
Now, let's substitute these values into the equation:
F = (q1 * q2) / r^2
F = (+2 × 10^–6 C) * (–2 × 10^–6 C) / (5.0 × 10^–2 m)^2
To multiply the charges, remember to multiply the numerical values and add the exponents of 10:
F = (2 * 10^–6) * (–2 * 10^–6) / (5.0 × 10^–2)^2
F = (–4 * 10^–12) / (5.0 × 10^–2)^2
Next, simplify the expression:
F = –4 * 10^–12 / (5.0 × 10^–2)^2
To square the term (5.0 × 10^–2)^2, square both the numerical value and the exponent:
F = –4 * 10^–12 / (5.0 × 10^–2 * 5.0 × 10^–2)
F = –4 * 10^–12 / (25 × 10^–4)
Now, rewrite 25 as 2.5 × 10:
F = –4 * 10^–12 / (2.5 × 10 * 10^–4)
Simplify and combine like terms:
F = –4 * 10^–12 / (2.5 × 10^–3)
Divide the numerical values and subtract the exponents of 10:
F = –1.6 × 10^–9 N
Therefore, the electric force between the +2 µC point charge and the –2 µC point charge separated by a distance of 5.0 cm is –1.6 × 10^–9 Newtons.