# Physics (acceleration)

1. Jasmine rode a horse down a path headed north. she started from rest and then accelerated at 0.5 m/s2 for 12 seconds and then travelled at a constant speed for 28 seconds.
a.) what was her velocity after 12 seconds?
b.) what was jasmines displacement after 10 seconds?
c.) how far did Jasmine travel during her 40 s ride?
d.) draw a velocity time graph for her motion

2. Bryce can ride his bicycle at an average speed of 18 m/s and Ally rides with an average speed of 23 m/s. ally gives bryce a 200 m Headstart in a 1 km (1000m) race. use a distance time graph to solve the following questions:
a.) who wins the race? explain your answer
b.) how many meters separate the 2 cyclists at the end of the race?

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1. 1.

a.)

Vf=Vi +at

Where

Vf=?
Vi=0m/s
a=0.5m/s^s
t=12s

Solve for Vf:

Vf=0m/s +(0.5m/s^2)*(12s)

Vf=6m/s

b.)

d=Vi*t + 1/2at^2

Where

d=?
Vi=0m/s
a=0.5m/s^s
t=10s

Solve for d:

d=0m/s*(12s) + 1/2(0.5m/s^2)(10s)^2

d=0 +25m

d=25m

c.)

d=Vi*t + 1/2at^2

Where

d=?
Vi=0m/s
a=0.5m/s^s
t=40s

Solve for d:

d=0m/s*(12s) + 1/2(0.5m/s^2)(40s)^2

d=0 +400m

d=400m

d.)

Plot distance Vs velocity

x axis =displacement and y=velocity

2.

****Plot distance on the x-axis and time (distance/velocity) on the y-axis.

***Remember, Bryce only has to travel 800m.

a.)

d=r*t

Where

r=velocity
t=?
and
d=displacement.

Bryce

d=800m
r=18m/s
t=?

800=18m/s*t

t=800m/18m/s

t=44.4s

Ally

d=1,000m
r=23m/s
t=?

1,000m=23m/s*t

t=1,000m/23m/s

t=43.5s

Ally wins.

b.)
Bryce wins the race in 43.4s. How far is Ally from the finish line when Bryce reaches the finish line?

d=18 m/s*43.4s

d1=781.2m

Total distance=d1+d2=781.2m + 200m=981.2m

1,000m-981.2m=18.8m=19.0m is the distance that separates them when the race ends.

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posted by Devron
2. Typo correction. Look for ^&***" for correction .

1.

a.)

Vf=Vi +at

Where

Vf=?
Vi=0m/s
a=0.5m/s^s
t=12s

Solve for Vf:

Vf=0m/s +(0.5m/s^2)*(12s)

Vf=6m/s

b.)

d=Vi*t + 1/2at^2

Where

d=?
Vi=0m/s
a=0.5m/s^s
t=10s

Solve for d:

d=0m/s*(12s) + 1/2(0.5m/s^2)(10s)^2

d=0 +25m

d=25m

c.)

d=Vi*t + 1/2at^2

Where

d=?
Vi=0m/s
a=0.5m/s^s
t=40s

Solve for d:

d=0m/s*(12s) + 1/2(0.5m/s^2)(40s)^2

d=0 +400m

d=400m

d.)

Plot distance Vs velocity

x axis =displacement and y=velocity

2.

****Plot distance on the x-axis and time (distance/velocity) on the y-axis.

***Remember, Bryce only has to travel 800m.

a.)

d=r*t

Where

r=velocity
t=?
and
d=displacement.

Bryce

d=800m
r=18m/s
t=?

800=18m/s*t

t=800m/18m/s

t=44.4s

Ally

d=1,000m
r=23m/s
t=?

1,000m=23m/s*t

t=1,000m/23m/s

t=43.5s

Ally wins.

b.)
^&***" Ally wins the race in 43.4s. How far is Bryce from the finish line when Ally reaches the finish line?" ***^&

d=18 m/s*43.4s

d1=781.2m

Total distance=d1+d2=781.2m + 200m=981.2m

1,000m-981.2m=18.8m=19.0m is the distance that separates them when the race ends.

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posted by Devron
3. Thank u so much :)

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posted by Samaira

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