Algebra 1

Solve 2x^2 + 7x = -8 using the Quadratic Formula.

A: No solution?

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  1. 2x^2 + 7x + 8 = 0

    B^2 = 7^2 = 49
    4AC = 4*2*8 = 64.

    Since B^2 is less than 4AC, there are
    no real solution. But there are 2 imaginary solutions:

    X = (-B +-sqrt(B^2-4AC))/2A
    X =(-7 +-sqrt(49-64))/4
    X = (-7+-sqrt(-15))/4
    X = (-7+-sqrt(15*-1))/4
    X = (-7+-(3.87i))/4

    X = -1.75 + 0.968i, and -1.75 - 0.968i.

    For 2 real solutions: B^2 => 4AC

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    posted by Henry

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