# Algebra 1

Solve 2x^2 + 7x = -8 using the Quadratic Formula.

A: No solution?

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1. 2x^2 + 7x + 8 = 0

B^2 = 7^2 = 49
4AC = 4*2*8 = 64.

Since B^2 is less than 4AC, there are
no real solution. But there are 2 imaginary solutions:

X = (-B +-sqrt(B^2-4AC))/2A
X =(-7 +-sqrt(49-64))/4
X = (-7+-sqrt(-15))/4
X = (-7+-sqrt(15*-1))/4
X = (-7+-(3.87i))/4

X = -1.75 + 0.968i, and -1.75 - 0.968i.

For 2 real solutions: B^2 => 4AC

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posted by Henry

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