write the equations in logarithmic form
216 = ^63 answer In(e^4.5)
49 = (1/7) ^-2 answer 2=log(3x)
To convert an equation into logarithmic form, we need to understand the relationship between exponential and logarithmic expressions.
The general exponential form is: b^x = y, where b is the base, x is the exponent, and y is the result.
The logarithmic form for the above equation is: log base-b of y = x.
Let's apply this concept to the given equations:
1. 216 = 6^3:
To express this equation in logarithmic form, we need to identify the base (b), exponent (x), and result (y).
- In the given equation, the base is 6 (b), the exponent is 3 (x), and the result is 216 (y).
- Therefore, the logarithmic form of the equation is: log base-6 of 216 = 3.
2. 49 = (1/7)^-2:
To express this equation in logarithmic form, let's first simplify the equation.
- We can rewrite (1/7)^-2 as (7/1)^2. This gives us 49 = (7/1)^2.
Again, let's identify the base (b), exponent (x), and result (y).
- In the given equation, the base is (7/1) or 7 (b), the exponent is 2 (x), and the result is 49 (y).
- Therefore, the logarithmic form of the equation is: log base-7 of 49 = 2.
I apologize, but it seems like there is a mistake in your third statement "2=log(3x)." Could you please provide the correct equation, and I'll be happy to help you convert it into logarithmic form?
No.
I don't know if you didn't read the responses to your last two questions or if you have deliberately ignored them.
The next time you post a question without your school subject, it will be deleted.