A 0.28 kg softball has a velocity of 16 m/s at an angle of 34° below the horizontal just before making contact with the bat. What is the magnitude of the change in momentum of the ball while it is in contact with the bat if the ball leaves the bat with a velocity of (a) 21 m/s, vertically downward, and (b) 21 m/s, horizontally back toward the pitcher?
I already solved the value of momentum using vector formulas but i cant get the answer when i'm already solving the momentum with those conditions (a and b). pls help
To find the magnitude of the change in momentum of the ball while it is in contact with the bat, we can use the principle of conservation of momentum, assuming the collision is elastic. The formula for momentum is given as:
Momentum = mass x velocity
The initial momentum of the ball is the product of the mass and the initial velocity, given by:
Initial Momentum = mass x initial velocity
To calculate the final momentum of the ball, we multiply the mass by the final velocity, which can be in two different directions depending on the given conditions:
(a) If the ball leaves the bat with a velocity of 21 m/s, vertically downward, the final momentum would be:
Final Momentum = mass x final velocity (downward)
(b) If the ball leaves the bat with a velocity of 21 m/s, horizontally back toward the pitcher, the final momentum would be:
Final Momentum = mass x final velocity (backward)
Now, to find the magnitude of the change in momentum, we need to calculate the difference between the final momentum and the initial momentum. This can be calculated as:
Change in Momentum = Final Momentum - Initial Momentum
You already solved the value of momentum using vector formulas for the initial momentum. Now, make sure you calculate the final momentum correctly with the given conditions for (a) and (b).
Once you have the initial and final momenta, plug in the values into the equation for change in momentum to find the magnitude.