Use the digits 1 though 9 once each. Fill in the 3x3 squares to make the sum of 777. Thanks.

if you have 9 squares and 9 digits, that only leaves on digit for each square.

I can't see how to add 3 single-digit numbers to get anything greater than 7+8+9=24.

Is there a trick, or something missing here?

I made the last row negative, so the sum of 235, 689, and -147 = 777. Personally, though, I think it's a mistake since I couldn't get 3 positive numbers to = 777.

To solve this puzzle and get the sum of 777 using the digits 1 through 9 once each in a 3x3 grid, we need to think strategically and logically. Here's a step-by-step guide:

1. Start by identifying the largest number we can make using these digits, which is 987 (9 + 8 + 7 = 24).
2. Since we need a sum of 777, we subtract the largest number from the desired sum: 777 - 987 = -210.

Now, let's divide the remaining sum (-210) into three groups:

3. Select three digits from the remaining six (1, 2, 3, 4, 5, and 6) that sum up to -210. This task is impossible since the sum of any three digits between 1 and 6 will be positive, not negative.
Therefore, it is not possible to solve this puzzle using the digits 1 through 9 once each in a 3x3 grid to make the sum of 777.