IF X IS AN ANGLE IN THE FIRST QUADRANT AND COSX= 3/5, FIND THE EXACT VALUE OF SIN2X
DONT UNDERSTAND, KNOW THAT THE COSX IS ON A 3,4,5 TRIANGLE
you should recognize the 3-4-5 right angled triangle.
so if cosx = 3/5
then sinx = 4/5
sin 2x = 2sinxcosx
= 2(4/5)(3/5) = 24/25
you can always check your result with a calculator.