Maths

Solving Simultaneous equation

Y=x-2
Y=x^2+3x-5

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asked by Becky
  1. use substitution

    x^2 + 3x - 5 = x-2
    x^2 + 2x - 3 = 0
    (x+3)(x-1) = 0
    x = -3 or x = 1

    check with Wolfram
    http://www.wolframalpha.com/input/?i=Y%3Dx-2+%2C+Y%3Dx%5E2%2B3x-5

    if x = -3, y = -3-2 = -5
    if x = 1 , y = 1-2 = -1

    x=-3, y=-5 ---> point (-3,-5)
    x = 1 , y = -1 --->point (1, -1)

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    posted by Reiny

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