# ALG

Solve. (If there is no solution, enter NO SOLUTION.)
y=x^2-x-3
y=-2x+3

(x,y) smaller value
larger value

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asked by KASAP
1. well, plug in -2x+3 for y:

-2x+3 = x^2-x-3
x^2+x-6 = 0
(x+3)(x-2) = 0

Looks like two solutions to me. I'm sure you can figure them out, eh?

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posted by Steve

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