# maths

Find the coordinates of the points of intersection of the straight line y = 3x - 6 with the parabola y = x^2 - 6x + 8 and solve Graphically.

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1. to solve algebraically, just solve

3x-6 = x^2-6x+8
x^2-9x+14 = 0
(x-7)(x+2) = 0

The graphical solution is at

http://www.wolframalpha.com/input/?i=solve+x^2-6x%2B8+%3D+3x-6

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posted by Steve

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