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If alpha and beta are the zeros of the polynomial p(x)=x^2+x+1 then find the value of 1÷alpha+1÷beta 2)alpha^2+beta^2

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asked by rinu
  1. I will use a for alpha and b for beta

    then from the properties of zeros of a quadratic
    a+b = -1
    ab = 1

    then 1/a + 1/b
    = (b+a)/(ab) = -1/1 = -1

    a^2 + b^2
    = (a+b)^2 - 2ab
    = (-1)^2 - 2(1)
    = 1 - 2 = -1

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    posted by Reiny

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