n-2n^2=0
n(1 - 2n) = 0 n = 0 or 1 - 2n = 0 n = 0 or n = 1/2
How did you get 1 - 2n = 0?
I took out a common factor of n expand n(1-2n) What do you get ?
Yes, but how did the first n in n(1 - 2n) go away?
It didn't, n = 0 became a solution. Are you not familiar that if you have a factored form = 0, such as (A)(B) = 0 , then A = 0 or B = 0 ???
First Name
Your Response