3/(s - 1) + 1 = 12/(s^2 - 1)
assuming you want to find the value(s) of s that make the equation true, place everything over the common denominator of (s^2-1) and clear fractions. Note that s=±1 are excluded, because that would involve division by zero.
3(s+1) + (s^2-1) = 12
s^2+3s-10 = 0
and I guess you can take it from there, no?