# Algebra

Solving quardratic equations using factoring.

2X^2+2X-4=0

The book says the answer is -2,1.

I got the -2,1 but not in the order of
-2,1.

I used FOIL to solve. When I use -2,1 I don't can not solve. When I use
1,-2. I can solve.

I am not clear.

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1. The order is not important. The answer is x=-2 or x=1

Verify by substituting for x
2(-2)^2+2(-2)-4=0
8-4-4=0
0=0

2(1)^2+2(1)-4=0
2+2-4=0
0=0

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