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The distance s in feet that a body falls in t seconds is given by the formula s=16t^2. If a body has been falling for 5 seconds, how far will it fall during the 6th second
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a body dropped from a height falls 16 feet during the first second, 48 feet the second second, 80 feet the third second, and so on. Find how far the body falls during the 7th second and how far it falls during the first 7 seconds
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the distance that a body falls through when dropped from a certain height varies directly with the square of the time of fall. A body falls through a total of 500m in 10 seconds. find the distance it falls through, in 9th second
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the distance that a body falls through when dropped from a certain height varies directly with the square of the time of fall. A body falls through a total of 500m in 10 seconds. find the distance it falls through, in 9th second
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5. 16t2 gives the distance in feet a freefalling object falls in t seconds. 16t2 + 10t gives the distance an object falls in t seconds when it is thrown down with an initial velocity of 10 feet per second. Use this polynomials
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The function s(t) = 16t^2 models the distance, s(t), in feet, that an object falls in t seconds. Find the number of seconds a sky diver is in free fall after jumping from a plane if she falls 192 feet before opening a parachute.
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The distance that an object falls is directly proportional to the square of the time of the fall, t. A person who is parachuting for the first time is told to wait 15 seconds before opening the parachute. If the person falls 64
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The approximate distance,S, in feet that an object falls in t seconds when dropped from a height can be found by using the formula S = 16t^2.In 8 seconds, the object will fall a. 256 feet b. 1,024 feet c. 1,084 feet d. 2,048 feet
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