Writ the equation in Logarithm form
25=(1/5)^2
a=b^c
Logb(a) = c
Log1/5(25) = 2
but 25 is not (1/5)^2
(1/5)^2 = 1/25
25 = 1/(1/5)^2 = (1/5)^-2
So, log1/525 = -2
loga = c*logb
regardless of base. Using b for the base, log_b(b)=1,so
logba = c
To write the equation 25=(1/5)^2 in logarithmic form, we need to understand the relationship between exponentiation and logarithms.
In logarithmic form, the equation a=b^c can be expressed as log base b of a = c.
Let's apply this concept to our equation.
Given: 25=(1/5)^2
Step 1: Identify the base.
The base is the number that is raised to a power. In this case, the base is 1/5.
Step 2: Identify the exponent.
The exponent is the power to which the base is raised. In this case, the exponent is 2.
Step 3: Rewrite the equation using logarithmic notation.
Using the formula log base b of a = c, we can write the equation as:
log base (1/5) of 25 = 2
So, the equation 25=(1/5)^2 in logarithmic form is:
log base (1/5) of 25 = 2