Complete the following fission reaction
1/0 n + 235/92 U ---> 236/92 Te + _____ +2 (1/2)n
a) 97/40 Zr
b) 99/40 Zr
c) 99/38 Sr
d) 95/42 Mo
e) 96/41 Y
Answer is A or B not sure
Either you've made a typo or this is a screwed up question. 236/92 can't be Te. It MUST be U. And what is 2(1/2)n? neutrons are 1/0.
What's with the 1/2n? neutrons are 1/0n
1/0 n + 235/92 U ---> 236/92 U ---> 137/52 Te + _____ +2 (1/2n)
Sorry my mistake!!!
I asked my instructor and he said he made a mistake with this question and it should be like this
1/0 n + 235/92 U ---> 236/92 U ---> 137/52 Te + _____ +2 (1/0 n)
ok Now we can do something.
Make the top numbers add up and the bottom numbers add up.
on the left.
top...1 + 235 = 236
bottom 0 + 92 = 92 which does nothing more than show that 236/92U is right.
Now to the next part of the reaction.
top: 236 = 137 + ? + (2*1) and solve for ?. I get 236-137-2 = 97
bottom: 92 = 52 + ? + 2*0 and solve for ?. I get 92-52-0 = 40
So the top number is 97 and the lower number is 40. The lower number of 40 is the atomic number; look on the periodic table and find element #40. Is that Zr? So now the full equation (just that part of it) is
236/92 U ==> 137/52 Te + 97/40 Zr + 2(1/0n)
To complete the given fission reaction, we need to balance the equation by ensuring that the total atomic mass and atomic number are conserved on both sides of the reaction.
In this case, we start with the fission of a neutron (symbolized as 1/0n) and uranium-235 (symbolized as 235/92U). The resulting products are tellurium-236 (symbolized as 236/92Te), a new element, and two other particles. We need to determine which element is produced.
To identify the element produced, we can use the conservation of both atomic mass and atomic number.
Looking at the atomic number, we see that the number of protons on the left side is 92 (from uranium-235). Therefore, the sum of the atomic numbers on the right side must also be 92.
Considering the atomic mass, the sum of the atomic masses on the left side is 1 + 235 = 236 (from the neutron and uranium-235). Therefore, the sum of the atomic masses on the right side must also be 236.
Taking all this into account, the answer is either option a) 97/40 Zr or option b) 99/40 Zr. Both options have an atomic number of 40 and an atomic mass of 97 or 99, respectively, which satisfies the conservation requirements.
The correct option between a) and b) depends on the specific isotopes of zirconium involved in the reaction. Therefore, it's essential to consult a periodic table or additional information to determine the exact isotope produced.