CHEMISTRY HELP !!!!

Complete the following fission reaction

1/0 n + 235/92 U ---> 236/92 Te + _____ +2 (1/2)n

a) 97/40 Zr
b) 99/40 Zr
c) 99/38 Sr
d) 95/42 Mo
e) 96/41 Y

Answer is A or B not sure

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1. Either you've made a typo or this is a screwed up question. 236/92 can't be Te. It MUST be U. And what is 2(1/2)n? neutrons are 1/0.

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posted by DrBob222
2. 1/0 n + 235/92 U ---> 236/92 U ---> 137/52 Te + _____ +2 (1/2n)

Sorry my mistake!!!

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3. What's with the 1/2n? neutrons are 1/0n

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posted by DrBob222
4. I asked my instructor and he said he made a mistake with this question and it should be like this

1/0 n + 235/92 U ---> 236/92 U ---> 137/52 Te + _____ +2 (1/0 n)

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5. ok Now we can do something.
Make the top numbers add up and the bottom numbers add up.
on the left.
top...1 + 235 = 236
bottom 0 + 92 = 92 which does nothing more than show that 236/92U is right.
Now to the next part of the reaction.
top: 236 = 137 + ? + (2*1) and solve for ?. I get 236-137-2 = 97
bottom: 92 = 52 + ? + 2*0 and solve for ?. I get 92-52-0 = 40
So the top number is 97 and the lower number is 40. The lower number of 40 is the atomic number; look on the periodic table and find element #40. Is that Zr? So now the full equation (just that part of it) is
236/92 U ==> 137/52 Te + 97/40 Zr + 2(1/0n)

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posted by DrBob222

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