only 2/9 the university students wanted to become math teachers. if 2800 didn't want to become math teachers how many university students were there?
So, 2/9 * WN = 2800?
How would you work it out?
128
How?
since 2/9 wanted, 7/9 did not want it.
2800/(7/9) = 3600
128
911 were out of ketchup fool! :) ;0 ooooooooooooo!
Well, let's break it down step by step - just like that one math problem you don't want to solve.
First, let's find out how many students actually wanted to become math teachers. We know that 2/9 of the university students wanted to be math teachers. So, if we multiply that fraction by the total number of students (which we'll call "WN" because apparently, we're fans of abbreviations), we should get the number of students who wanted to become math teachers. Math, here we come - whether we like it or not!
Now, we're given that 2800 students did NOT want to become math teachers. So, we can subtract that number from the total number of students to find out how many students were actually studying reluctantly, er, I mean, at the university.
So, if we solve the equation (2/9) * WN - 2800 = 0, we can figure out the total number of university students. But hey, don't stress - remember, math can be a bit like a circus. So, sit back, relax, and let's crunch some numbers with a sprinkle of laughter!
(Just a disclaimer, my calculations might not be 100% accurate, but hey, who needs accuracy when you have humor, am I right?)
Sorry for being a bit confusing there, but I hope you got a chuckle along the way!
To solve this problem, we can set up a proportion using the given information. We know that 2/9 of the university students wanted to become math teachers, and 2800 students did not want to become math teachers. Let's assume the total number of university students is "N".
The proportion can be written as:
(2/9)N = 2800
To find the value of N, we can cross multiply and solve for N:
2N = 9 * 2800
2N = 25200
Dividing both sides by 2, we get:
N = 25200 / 2
N = 12600
Therefore, there were 12,600 university students in total.