What is the % mass/volume of a 3.00 M solution of NaCl?
assume 1 liter. Then there must be 3moles, or 3*58.44 grams
Percent m/v= 58.44/1000= 5.8Percent m/v
I still don't understand
I got confused
actually I lost a three.
Percent m/v= 3*58.44/1000= 3*5.8Percent m/v
http://www.enotes.com/homework-help/what-mass-volume-3-00-m-solution-nacl-375701
So i multiply 3*5.8 and that will be the m/v
yes
To determine the % mass/volume of a solution, we need to know the mass of the solute (NaCl) and the volume of the solution.
The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. In this case, we have a 3.00 M solution of NaCl.
To find the mass of NaCl in the solution, we need to know the molar mass of NaCl, which is approximately 58.44 grams/mol.
The molarity formula is as follows:
M = moles of solute / volume of solution (in liters)
Since we know the molarity and want to find the mass/volume percentage, we need to rearrange the formula to solve for the mass of solute:
moles of solute = M x volume of solution (in liters)
To calculate the mass of NaCl in the solution, we multiply the moles of NaCl by its molar mass:
mass of NaCl = moles of NaCl x molar mass of NaCl
Finally, to find the % mass/volume, we divide the mass of NaCl by the volume of the solution and multiply by 100:
% mass/volume = (mass of NaCl / volume of solution) x 100
Using this information and the given molarity of 3.00 M NaCl, you can calculate the % mass/volume of the solution.