chemistry

If you have a 29.6 mass percent KCl in benzene,what is the new boiling point?

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asked by brandie
  1. 29.6% (w/w) is 29.6 g KCl/100 g solution.
    That is 29.6g KCl in (29.6g KCl + 70.4 g H2O.
    mols KCl = grams/molar mass = ?
    kg H2O = 0.0704
    molality of the solution is mols/kg solvent
    Then delta T = i*Kb*m
    i = 2 for KCl. Solve for delta T and add to 100 C to find new boiling point.

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    posted by DrBob222

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