# chemistry

What would Qc be if the volume of the container decreased by a factor of 1.774 for the following reaction?
PH3(g) + BCl3(g) → PH3BCl3(s)
KC = 534.8
at 353.0oC

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asked by Andy
1. If the volume decreases (by say a factor of 2) that will double the (PH3) and double (BCl3). For a factor of 1.774 concn will be increased for EACH by 1.774. Remember the solid doesn't appear in Kc.
Kc = 1/(PH3)(BCl3)
So Kc > Q = 534.8/(1.774)(1.774)

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posted by DrBob222

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