What mass of CO2 could be absorbed by 1.37 g of CaO?

What volume would this CO2 occupy at STP?

To determine the mass of CO2 that can be absorbed by 1.37 g of CaO, we need to consider the stoichiometry of the reaction between CaO and CO2. The balanced chemical equation for the reaction is:

CaO + CO2 -> CaCO3

According to the equation, one mole of CaO reacts with one mole of CO2 to form one mole of CaCO3.

Step 1: Calculate the molar mass of CaO (calcium oxide) and CO2 (carbon dioxide).
The molar mass of CaO = 40.08 g/mol (calcium has a molar mass of 40.08 g/mol, and oxygen has a molar mass of 16.00 g/mol)
The molar mass of CO2 = 12.01 g/mol (carbon has a molar mass of 12.01 g/mol, and oxygen has a molar mass of 16.00 g/mol)

Step 2: Calculate the number of moles of CaO.
Number of moles = mass / molar mass
Number of moles of CaO = 1.37 g / 56.08 g/mol (molar mass of CaO)
Number of moles of CaO ≈ 0.02445 mol

Step 3: Determine the stoichiometric ratio.
According to the balanced equation, each mole of CaO reacts with 1 mole of CO2.
Thus, the number of moles of CO2 that can be absorbed is also approximately 0.02445 mol.

Step 4: Calculate the mass of CO2 absorbed.
Mass of CO2 = number of moles x molar mass
Mass of CO2 = 0.02445 mol x 44.01 g/mol (molar mass of CO2)
Mass of CO2 ≈ 1.075 g

Therefore, approximately 1.075 g of CO2 can be absorbed by 1.37 g of CaO.

To determine the volume of CO2 at STP (Standard Temperature and Pressure), we need to use the Ideal Gas Law equation:

PV = nRT

Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = the ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)

At STP, the pressure (P) is equal to 1 atm, and the temperature (T) is equal to 273.15 K.

Step 1: Convert moles of CO2 to volume.
Using the Ideal Gas Law equation, rearrange it to solve for V:
V = (nRT) / P

Step 2: Plug in the values.
V = (0.02445 mol x 0.0821 L·atm/(mol·K) x 273.15 K) / 1 atm

Step 3: Calculate the volume.
V ≈ 0.564 L

Therefore, approximately 0.564 liters (or 564 mL) is the volume that the absorbed CO2 would occupy at STP.