# algebra

write the equation in logarithm form
a) 343=7^3
b) 25-(1/5)-^2
c A=bc

Thank you for your help. I have no idea how to do this problem and I am getting stress.

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1. a) just take logs of both sides. Since log(x^n) = n*logx, we have

log 343 = 3*log 7
Now, it would help to use base 7 for the logs, to make the nice and pretty equation

log7343 = 3

since 5^2 = 25, 5^-2 = 1/5^2 = 1/25
So, (1/5)^-2 = 1/(1/25) = 25
Using base 1/5 logs, that is

log1/525 = -2

A = bc
log A = log b + log c

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posted by Steve
2. Thank you very much Steve for explaining it like you did, that was a great help. It is greatly appreciated. Have a wonderful day.

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posted by Mary

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