In the meantime I got the last one but this one I can't figure...
Divide. [(x^2-9)/(x-5)]/(x+3)
• (x-3)/(x-5)
• (x-5)/(x-3)
• [(x+3)/(x-3)]/(x-5)
• (x+3)/(x-5)
How?
x^2-9 - (x+3)(x-3)
so, cancelling the x+3 factors, you have
(x-3)/(x-5)
Thanks so much
To divide the expression [(x^2-9)/(x-5)]/(x+3), we can simplify it step by step.
Step 1: Factorize the numerator and denominator of the main fraction.
The numerator, x^2 - 9, is a difference of squares and can be factored as (x+3)(x-3).
The denominator, x-5, is already factored.
Therefore, the expression becomes: [(x+3)(x-3)/(x-5)]/(x+3)
Step 2: Simplify the expression by canceling out common factors.
Notice that (x+3) is present in both the numerator and denominator of the main fraction. We can cancel them out.
The expression now simplifies to: (x-3)/(x-5)
Therefore, the correct answer is (x-3)/(x-5).