# math

A truck has 5.9L engine in it. 5.9L of the overall displacement in 6 cylinders each 102mm bore (diameter) and 120mm stroke (length). Engine operates at 16.3:1 compression ratio and with 6psi (0.41atm) of boost cruising at 1600rpm.

What is the volume of ONE cylinder? Then add 6% to account for combustion chamber in the cylinder head.

What i've got to far is this:

V= pie*r^2*h

V= 3.14*51^2*120= 19,216.8mm

19,216.8mm*.06= 1,153.008

19,216.8mm+1,153.008= 20, 369.808mm^3

Am i even close? Thanks

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1. Your work is correct, but probably made some mistake with the calculator.

Volume = πr²h*1.06
= π(51)^2(120)×1.06;
=330847.2π
=1039387.133 mm³ approximately.

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posted by MathMate

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