5. A bag contains 7 green marbles and 4 white marbles. You select a marble at random. What are the odds in favor of picking a green marble?

A. 7:11**?
B. 7:4
C. 4:7
D. 3:7 ------------------------------------ 6. Food Express is running a special promotion in which customers can win a free gallon of milk with their food purchase if there is a star on their receipt. So far, 147 of the first 156 customers have not received a star on their receipts. What is the experimental probability of winning a free gallon of milk?

A. 11/156
B. 49/52
C. 2/39
D. 3/52

7. A bag contains 7 green marbles, 9 red marbles, 10 orange marbles, 5 brown marbles, and 10 blue marbles. You choose a marble, replace it, and choose again. Find P(red, then blue).

A. 77/164
B. 19/41*
C. 90/1681
D. 45/41

#5. Nope

The probability is 7/11, but the odds are 7:4

That is, 7 chances for and 4 against.

#6
There are 147 without a star, so 9 with a star. So

P(star) = 9/156 = 3/52

#7
total marbles: 41
P(red) = 9/41
P(blue) = 10/41
P(red,blue) = 9/41 * 10/41 = 90/1681

You can't just add the probabilities. If so, then by specifying enough drawings, you'd eventually add up enough fractions to get more than 1. Actually, by specifying more and more drawings, the chance of getting them ALL keeps getting smaller.

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The odds in favor of picking a green marble would be given by:

Number of green marbles : Number of non-green marbles = 7:4

So the odds in favor of picking a green marble are 7 to 4.

The probability of choosing a red marble on the first draw is 8/43, because there are 8 red marbles in a total of 43 marbles. After replacing this marble back into the bag, there are still 12 blue marbles left in a total of 43 marbles. Therefore, the probability of choosing a blue marble on the second draw, given that a red marble was chosen on the first draw, is also 12/43.

Using the multiplication rule of probability, we can find the probability of both events occurring as:

P(red, then blue) = P(red) x P(blue | red)
P(red, then blue) = (8/43) x (12/43)
P(red, then blue) = 96/1849

So the probability of choosing a red marble on the first draw and a blue marble on the second draw is 96/1849.

agreed

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That doesn't make sense. Please let me know if you have any questions or if there's anything I can help you with.

A bag contains 7 green marbles and 4 white marbles. You select a marble at random. What are the odds in favor of picking a green marble?

A bag contains 5 green marbles, 8 red marbles, 11 orange marbles, 7 brown marbles, and 12 blue marbles. You choose a marble, replace it, and choose again. What is P(red, then blue)?

You own 5 pairs of jeans and want to take 2 of them with you on vacation. In how many ways can you choose 2 pairs of jeans?