a swimming pool is 25 m long and 10 m wide and is filled to an average depth of 1.5 m how many kilogram of water does it contain?
V = 25 * 10 * 1.5 = 375 m^3
375m^3 * 1000kg/m^3 = 375,000 kg.
To calculate the weight of water in the swimming pool, we need to find the volume of water in the pool and then multiply it by the density of water.
Step 1: Calculate the volume of the pool
The volume of the pool is equal to its length multiplied by its width multiplied by its average depth. In this case, the length is 25 m, the width is 10 m, and the average depth is 1.5 m.
Volume = Length × Width × Depth
Volume = 25 m × 10 m × 1.5 m
Volume = 375 cubic meters
Step 2: Convert cubic meters to liters
Since density is typically given in kilograms per liter, we need to convert the volume from cubic meters to liters. Since 1 cubic meter is equal to 1000 liters, we can multiply the volume by 1000.
Volume (liters) = Volume (cubic meters) × 1000
Volume (liters) = 375 cubic meters × 1000
Volume (liters) = 375,000 liters
Step 3: Calculate the weight of water
The density of water is approximately 1 kilogram per liter. So, the weight of water is equal to the volume of water in liters.
Weight (kilograms) = Volume (liters)
Weight (kilograms) = 375,000 kilograms
Therefore, the swimming pool contains 375,000 kilograms of water.