# physics

A 9.0 §Ù resistor and a 53.0 §Ù resistor are connected in parallel to a battery, and the current in the 9.0 §Ù resistor is found to be 1.41 A. Find the potential diﬀerence across the bat- tery.

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1. R1 = 9.0 ohms
R2 = 53 ohms
I1 = 1.41 Amps = current through R1.

V = I1 * R1 = 1.41 * 9 = 12.69 Volts. =
voltage across battery.

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posted by Henry

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