A 9.0 §Ù resistor and a 53.0 §Ù resistor are connected in parallel to a battery, and the current in the 9.0 §Ù resistor is found to be 1.41 A. Find the potential difference across the bat- tery.
R1 = 9.0 ohms
R2 = 53 ohms
I1 = 1.41 Amps = current through R1.
V = I1 * R1 = 1.41 * 9 = 12.69 Volts. =
voltage across battery.
To find the potential difference across the battery, we can use Ohm's Law which states that V = I * R, where V is the potential difference (in volts), I is the current (in amperes), and R is the resistance (in ohms).
In this case, we know the current (I) flowing through the 9.0 §Ù resistor, so we can use that to find the potential difference across the battery. However, we need to consider that the 9.0 §Ù resistor and the 53.0 §Ù resistor are connected in parallel.
When resistors are connected in parallel, the potential difference across each resistor is the same. Therefore, the potential difference across the battery is equal to the potential difference across the 9.0 §Ù resistor.
Substituting the given values into Ohm's Law, we have:
V = I * R
V = 1.41 A * 9.0 §Ù
V = 12.69 V
Therefore, the potential difference across the battery is 12.69 volts.