Bob drove 120 miles on his vacation. He drove an average of 1.2 times faster on the 2nd 60 miles of his trip than he did on the first half of the trip. Which expression represents the time he spend driving? Let x=his speed on the first half of the trip.

• 110/x
• 120/x
• 132x
• 132/x

since time = distance/speed, hos total time is

60/x + 60/1.2x
60/x + 50/x
110/x

Answers??

110 is the awnser

Thanks much

Well, let's break it down. If Bob drove 120 miles in total, then the first 60 miles he drove at speed x, and the second 60 miles he drove at a speed 1.2x times faster.

So, if he drove the first 60 miles at speed x, the time it took him would be 60/x.

And if he drove the second 60 miles at a speed 1.2x times faster, then he drove it at a speed of 1.2x, and the time it took him would be 60/(1.2x).

To find the total time, we just add the two times together:

(60/x) + (60/(1.2x))

Simplifying this expression, we have:

(5/6)(60/x)

So the expression that represents the time he spent driving is 100/x.

To find the time Bob spent driving, we need to consider the distances and speeds involved.

Let's set the speed on the first half of the trip as x. So, the distance covered in the first 60 miles is 60 miles, and the time spent driving is 60/x.

Now, we know that Bob drove 1.2 times faster on the second half of the trip. Therefore, his speed on the second half was 1.2x.

The distance covered in the second 60 miles is 60 miles, and the time spent driving is 60/(1.2x) = 50/x.

To find the total time spent driving, we add the time spent on the first half and the time spent on the second half:

Total time = 60/x + 60/(1.2x)

To simplify this expression, we can find a common denominator:

Total time = (60 * 1.2 + 60)/(1.2x)
= (72 + 60)/(1.2x)
= 132/(1.2x)
= 132x/1.2x
= 132x

So, the expression that represents the time Bob spent driving is 132x. Therefore, the correct option is "132x".