Two vehicles are moving at a velocity of 100km/hr and 60km/hr the magnitude along the road is 500km and the vehicle with a vehicle with a velocity of 100km/hr began the journey 2.5 hrs ealier.CALCULATE the distance the vehicle with 60km/hr travelled to catch up the other
a vehicle going 60 can never catch up with one going 100, if the faster one has a head start.
To calculate the distance the vehicle with a velocity of 60 km/hr traveled to catch up with the other vehicle, we need to consider the relative velocity between the two vehicles.
First, let's determine the time it takes for the two vehicles to meet. Since the vehicle with a velocity of 100 km/hr began the journey 2.5 hours earlier, it will already be 100 km/hr × 2.5 hr = 250 km ahead when the other vehicle starts.
Now, let's focus on the relative velocity between the two vehicles. The relative velocity can be calculated by subtracting the velocity of the slower vehicle from the velocity of the faster vehicle:
Relative velocity = 100 km/hr - 60 km/hr = 40 km/hr
To find the time it takes for the two vehicles to meet, we can divide the relative distance (250 km) by the relative velocity (40 km/hr):
Time taken to meet = 250 km / 40 km/hr = 6.25 hours
Now that we have the time it takes for the two vehicles to meet, we can calculate the distance traveled by the vehicle with a velocity of 60 km/hr. We know its velocity is 60 km/hr, and the time taken to meet is 6.25 hours:
Distance traveled by the vehicle with 60 km/hr = Velocity × Time taken = 60 km/hr × 6.25 hr = 375 km
Therefore, the vehicle with a velocity of 60 km/hr traveled a distance of 375 km to catch up with the other vehicle.