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I don't understand how log2 √(1/2) turned into log2 2^(1/2). Quote: You will have to know the 3 prime properties of logs 1. logk (AB) = logk A + logk B 2. logk(A/B) = logk A  logk B 3. logk (A^n) = n logk A where k is any
asked by Anonymous on June 24, 2015 
Math
I don't understand how log2 √(1/2) turned into log2 2^(1/2). Quote: You will have to know the 3 prime properties of logs 1. logk (AB) = logk A + logk B 2. logk(A/B) = logk A  logk B 3. logk (A^n) = n logk A where k is any
asked by Anonymous on June 24, 2015 
Math
I don't understand how log2 √(1/2) turned into log2 2^(1/2). Quote: You will have to know the 3 prime properties of logs 1. logk (AB) = logk A + logk B 2. logk(A/B) = logk A  logk B 3. logk (A^n) = n logk A where k is any
asked by Anonymous on June 24, 2015 
Urgent math
i need help with these two homework problems Use the Laws of Logarithms to combine the expression into a single logarithm log2 5 − 5 log2 x + 1/2 log2(x + 1) Solve the logarithmic equation for x log2(x + 2) + log2(x − 1) = 2
asked by Emma on August 3, 2015 
Math
Hello! Could someone please take a look at the problem below and let me know if I made mistakes in simplifying the given equation? I'm quite certain that I did make a mistake somewhere because the original equation and its
asked by Constantine on May 31, 2015 
math30
1.Use the laws of logarithms to express log2 (6) â€“ log2 (3) + 2log2 (8)^1/2 as a single logarithm; then evaluate. 2. For logy = log(0.5x â€“ 3) + log2, express y as a function of x.
asked by alejandro on July 10, 2012 
math
solve the equation log2(x+4)log4x=2 the 2 and 4 are lower than the g This is what I got: log2(x+4)+log2(4^x)=2 log2((x+4)*4^x)=2 4^x(x+4)=4 x=0 is a solution???
asked by anonymous on January 9, 2013 
Logarithms
I'm working on logarithmic equations and I'm stuck on how my book arrives at the next step. First, they use the change of base formula on, log(sqrt(2))(x^3  2) (sqrt(2)) is the base,changing to base 2 log(sqrt(2))(x^3  2)=
asked by Helper on March 9, 2011 
Math Algebra 2
How do I put log in a TI84 calculator. #1.Express the logarithm in terms of log2M and log2N: log2(MN)4 #2. Express the logarithm in terms of log2M and log2N: log2 the cube root of M2N #3. Express the logarithm in terms of log2M
asked by AM on February 5, 2013 
Math  Logarithmic
Solve: 2^(5x6) = 7 My work: log^(5x6) = log7 5x  6(log2) = log7 5x = log7 + 6(log2) x = (log7 + log2^6) / 5 And textbook answer: (log7) / (log2) What did I do wrong?
asked by Anonymous on December 13, 2007